(x^2+2x)-(x^2+2x+2)=1

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Solution for (x^2+2x)-(x^2+2x+2)=1 equation: 


Simplifying
(x2 + 2x) + -1(x2 + 2x + 2) = 1

Reorder the terms:
(2x + x2) + -1(x2 + 2x + 2) = 1

Remove parenthesis around (2x + x2)
2x + x2 + -1(x2 + 2x + 2) = 1

Reorder the terms:
2x + x2 + -1(2 + 2x + x2) = 1
2x + x2 + (2 * -1 + 2x * -1 + x2 * -1) = 1
2x + x2 + (-2 + -2x + -1x2) = 1

Reorder the terms:
-2 + 2x + -2x + x2 + -1x2 = 1

Combine like terms: 2x + -2x = 0
-2 + 0 + x2 + -1x2 = 1
-2 + x2 + -1x2 = 1

Combine like terms: x2 + -1x2 = 0
-2 + 0 = 1
-2 = 1

Solving
-2 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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